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Chemistry
When BrO 3- ion reacts with Br- ion in acidic solution Br 2 is liberated. The equivalent weight of KBrO 3 in this reaction is
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Q. When $BrO _{3}^{-}$ ion reacts with $Br^-$ ion in acidic solution $Br _{2}$ is liberated. The equivalent weight of $KBrO _{3}$ in this reaction is
Redox Reactions
A
$M / 8$
11%
B
$M / 3$
33%
C
$M / 5$
46%
D
$M / 6$
10%
Solution:
$2 \overset{+5}{Br}$ (from $\left. BrO _{3}^{-5}\right)+10 e^{-} \rightarrow \overset{0}{Br _{2}}$
$\therefore $ Eq. wt. of $KBrO _{3}=\frac{M}{5}$