Question

When benzene sulphonic acid and p-nitrophenol are treated with $ NaHC{{O}_{3}} $ the gases released respectively are

• A. $ S{{O}_{2}},\,C{{O}_{2}} $
• B. $ C{{O}_{2}},\,C{{O}_{2}} $
• C. $ S{{O}_{2}},\,NO $
• D. $ S{{O}_{2}},\,N{{O}_{2}} $

Answer 1

Answer: (B)

Benzene sulphonic acid and p-nitrophenol react with $ NaHC{{O}_{3}} $ and evolve $ C{{O}_{2}} $ gas.
Because benzene sulphonic acid and p-nitrophenol are stronger acids, so they are capable of to evolve $ C{{O}_{2}} $ with $ NaHC{{O}_{3}} $ . $ HCO_{3}^{-}+{{H}^{+}}\xrightarrow{{}}{{H}_{2}}O+C{{O}_{2}}\uparrow $