1. Tardigrade
  2. Question
  3. Chemistry
  4. When attraction between A-B is more than that of A-A and B - B, the solution will show

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Q. When attraction between $A-B$ is more than that of $A-A$ and $B - B$, the solution will show

ManipalManipal 2018

Solution:

When $A-B$ attractions are greater than $A-A$ and $B-B$, then less vapours are formed and hence, solution shows negative deviation.