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Q. When aluminum oxide $\left( Al _{2} O _{3}\right)$ is electrolyzed for the production of aluminum metal. For a given quantity of electricity, the number of moles of aluminum obtained if the volume of $O _{2}$ gas obtained is $201.6$ liter measured at NTP is:

Electrochemistry

Solution:

Number of equivalent of oxygen $=\frac{201.6}{5.6}=36$
(Equivalent volume of oxygen $=5.6$ liter at N.T.P.)
$\therefore$ Number of equivalent of $Al =36$
Mass of aluminum $=36 \times 9\, g$
Number of moles of aluminum $=\frac{36 \times 9}{27}=12$