Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. When aluminium is bombarded with fast neutrons, it changes into sodium with emission of particle $x$ according to the equation ${ }_{13}^{27} \mathrm{Al}+{ }_0^1 \mathrm{n} \rightarrow{ }_{11}^{24} \mathrm{Na}+\mathrm{x}$

What is $x$ ?

NTA AbhyasNTA Abhyas 2020Nuclei

Solution:

The mass number of $x=27+1-24=4$ and its atomic number $=13+0-11=2.$
Hence particle $x$ is the helium nucleus, which is called an alpha particle