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  4. When air is replaced by a dielectric medium of constant K, the maximum force of attraction between two charges separated by a distance

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Q. When air is replaced by a dielectric medium of constant K, the maximum force of attraction between two charges separated by a distance

AIPMTAIPMT 1999Electrostatic Potential and Capacitance

Solution:

In air the force of attraction between two charges is $F _{ a }=\frac{1}{4 \pi \epsilon_{0}} \frac{ q _{1} q _{2}}{ r ^{2}}$
In dielectric medium the force of attraction between two charges is $F _{ d }=$
$$
\frac{1}{4 \pi K \epsilon_{0}} \frac{ q _{1} q _{2}}{ r ^{2}}=\frac{ F _{ a }}{ K }
$$
Thus, force decreases K-times.