Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
When acetamide is treated with Br2 and caustic soda, the product formed is
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. When acetamide is treated with $ Br_2 $ and caustic soda, the product formed is
MHT CET
MHT CET 2008
A
$ N $ -bromamide
B
bromoacetic acid
C
methanamine
D
ethanamine
Solution:
Amides react with bromine and caustic soda to give their corresponding primary amines. Thus, acetamide gives methanamine. This reaction is known as Hofmann’s bromamide degradation reaction.
$\underset{\text{acetamide}}{H_3C-\overset{\underset{||}{O}}{C} - NH_2} + Br_2 + 4KOH \ce{->[343K]}$
$2 KBr + K _{2} CO _{3}+ \underset{\text{methanamine}}{H _{3} C - NH _{2}}+2 H _{2} O$