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Q. When acetamide is reacted with $ NaOBr,$ then product formed is:

Jharkhand CECEJharkhand CECE 2006

Solution:

When acetamide is treated with $NaBr$ or $Br_2/NaOH $ Hofmann degradation reaction takes place and a primary amine is obtained as:
$CH_3CONH_2 + NaOBr $ or $Br_2/NaOH \rightarrow \underset{\text{methyl amine or methanamine}}{CH_3NH_2}+ 2NaBr + NaHCO_3 + H_2O$