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Q. When a solution containing $w\, g$ of urea in $1 \,kg$ of water is cooled to $-0.372^{\circ} C , 200\, g$ of ice is separated. If $K_{f}$ for water is $1.86 \,K \cdot kg / mol , w$ is

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Solution:

Mass of water present in the solution at the freezing pt. $=1000$

$-200=800\, g$

$\Delta T_{f} =0.372=\frac{1000 \times k_{f} w}{60 \times 800}$

$=\frac{1000 \times 1.86 \times w}{60 \times 800} $

or $ w =9.6\, g .$