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  4. When a mixture consisting of 10 moles of SO 2 and 15 moles of O 2 was passed over a catalyst, 8 moles of SO 3 were formed. Thus, percentage yield of SO 3 wrt SO 2 is

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Q. When a mixture consisting of $10$ moles of $SO _2$ and $15$ moles of $O _2$ was passed over a catalyst, $8$ moles of $SO _3$ were formed. Thus, percentage yield of $SO _3$ wrt $SO _2$ is

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Solution:

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If $10\, mol \, SO _2$ is taken, $O _2$ required is $5 \, mol$, forming $10 \, mol\, SO _3$
But $SO _3$ actual formed $=8 mol$
Thus, percentage yield of $SO _3$ wrt $SO _2=\frac{8}{10} \times$ $100=80 \%$