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Q. When a charged particle moving with velocity $\vec{ v }$ is subjected to a magnetic field of induction $\vec{ B }$ the force on it is non-zero. This implies that

JIPMERJIPMER 2008Moving Charges and Magnetism

Solution:

When a charged particle $q$ is moving in a uniform magnetic field $\vec{ B }$ with velocity $\vec{ v }$ such that angle between $\vec{ v }$ and $\vec{ B }$ be $\theta$, then due to interaction between the magnetic field produced due to moving charge and magnetic force applied, the charge $q$ experiences a force which is given by
$F=q v B \sin \theta$
If $\theta=0^{\circ}$ or $180^{\circ}$, then $\sin \theta=0$
$\therefore F=q v B \sin \theta=0$
Since, force on charged particle is non-zero, so angle between $\vec{ v }$ and $\vec{ B }$ can have any value other than zero and $180^{\circ}$.
Note : Force experienced by the charged particle is Lorentz force.