Q.
When a brown compound of $Mn ( A)$ is treated with $HCl$, it gives a gas $(B)$. The gas $(B)$ taken in excess reacts with $NH _{3}$ to give an explosive compound $(C)$. The compounds $A, B$ and $C$ are;
A
BI
C
(a)
$MnO_2$
$Cl_2$
$Ncl_3$
(b)
$Mno$
$Cl_2$
$NH_4Cl$
(c)
$Mn_3O_4$
$Cl_2$
$NCl_3$
(d)
$MnO_3$
$Cl_2$
$NCl_2$
A | BI | C | |
---|---|---|---|
(a) | $MnO_2$ | $Cl_2$ | $Ncl_3$ |
(b) | $Mno$ | $Cl_2$ | $NH_4Cl$ |
(c) | $Mn_3O_4$ | $Cl_2$ | $NCl_3$ |
(d) | $MnO_3$ | $Cl_2$ | $NCl_2$ |
Solution: