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Q. When a brown compound of $Mn ( A)$ is treated with $HCl$, it gives a gas $(B)$. The gas $(B)$ taken in excess reacts with $NH _{3}$ to give an explosive compound $(C)$. The compounds $A, B$ and $C$ are;
A BI C
(a) $MnO_2$ $Cl_2$ $Ncl_3$
(b) $Mno$ $Cl_2$ $NH_4Cl$
(c) $Mn_3O_4$ $Cl_2$ $NCl_3$
(d) $MnO_3$ $Cl_2$ $NCl_2$

KCETKCET 2016The d-and f-Block Elements

Solution:

When brown compound $Mn _{3} O _{4}$ is treated with $HCl$, it gives chlorine gas.
$ Mn _{3} O _{4}+8 HCl \rightarrow 3 MnCl _{2}+4 H _{2} O + Cl _{2} \uparrow $
Chlorine gas taken in excess reacts with ammonia to give an explosive compound $NCl _{3} .$
$ NH _{3}+3 Cl _{2} \text { (excess) } \rightarrow NCl _{3}+3 HCl $
The compounds $A , B$ and $C$ are $A = Mn _{3} O _{4}, B = Cl _{2}, C = NCl _{3}$