Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. When a body is projected vertically up from the ground with certain velocity, its potential energy and kinetic energy at a point A are in the ratio $2 : 3$. If the same body is projected with double the previous velocity, then at the same point A the ratio of its potential energy to kinetic energy is

KEAMKEAM 2015Work, Energy and Power

Solution:

Let in the first case, the total energy at the throwing point be $5 E$.
$KE$ at a particular height $=3 E$, potential energy at the height $=2 E$
As velocity of throw is doubled, kinetic energy becomes 4 times.
$\therefore $ Total $KE$ at the throwing point $20\, E$
$PE$ at the same height $=2 E$ (will remain same as the previous value) and $KE$ at the same height $=18\, E$
$\frac{P E}{K E}=\frac{2 E}{18 E}=\frac{1}{9}=1: 9$