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  4. When a ball is thrown up vertically with velocity V0, it reaches a maximum height of ‘h’. If one wishes to triple the maximum height then the ball should be thrown with velocity

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Q. When a ball is thrown up vertically with velocity $V_0$, it reaches a maximum height of ‘$h$’. If one wishes to triple the maximum height then the ball should be thrown with velocity

Motion in a Straight Line

Solution:

$H_{max} \propto u^2$
$ \therefore u \propto \sqrt{H_{max}}$
i.e., to triple the maximum height, ball should be thrown with velocity$\sqrt{3} V_0$