1. Tardigrade
  2. Question
  3. Chemistry
  4. When 800 mL of 0.5 M nitric acid is heated in a beaker, its volume is reduced to half and 11.5 g of nitric acid is evaporated. The molarity of the remaining nitric acid solution is x × 10-2 M. (Nearest Integer) (Molar mass of nitric acid is 63 g mol -1 )

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. When $800\, mL$ of $0.5\, M$ nitric acid is heated in a beaker, its volume is reduced to half and $11.5 \, g$ of nitric acid is evaporated. The molarity of the remaining nitric acid solution is $x \times 10^{-2} M$. (Nearest Integer)
(Molar mass of nitric acid is $63\, g \, mol ^{-1}$ )

JEE MainJEE Main 2022Some Basic Concepts of Chemistry

Solution:

$ n _{ HNO _3}=0.5 \times 0.8$
$ =0.4 $ mole
$\left( n _{ HNO _3}\right)_{\text {remains }}=0.4-\frac{11.5}{63}$
$ =0.4-0.1825 $
$ =0.2175 $
Molarity $=\frac{0.2175}{400} \times 1000$
$ =\frac{0.2175}{0.4} $
$ =0.5437 mole / lit . $
$\simeq 0.54 mole / lit . $
$ =54 \times 10^{-2} mol / lit .$