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Q. When $5.1\, g$ of solid $NH _{4} HS$ is introduced into a two litre evacuated flask at $27^{\circ} C , 20 \%$ of the solid decomposes into gaseous ammonia and hydrogen sulphide. The $K _{ p }$ for the reaction at $27^{\circ} C$ is $x \times 10^{-2}$. The value of $x$ is ________. (Integer answer)
$\left[\right.$ Given $\left.R =0.082\, L\, atm\, K ^{-1} mol ^{-1}\right]$

JEE MainJEE Main 2021Equilibrium

Solution:

moles of $ NH _{4} HS$ initially taken $=\frac{5.1 \,g }{51\, g / mol } $
$=0.1 \,mol$
volume of vessel $=2 \ell$
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$\Rightarrow $ partial pressure of each component
$P=\frac{n R T}{V}=\frac{0.1 \times 0.2 \times 0.082 \times 300}{2} $
$=0.246 \,atm$
$\Rightarrow k _{P}= P _{ NH _{3}} \times P _{ H _{2} S }$
$=(0.246)^{2}=0.060516 $
$=6.05 \times 10^{-2}$
$\Rightarrow 6$