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Q. When 32.25 g of ethyl chloride is subjected to dehydrohalogenation reaction, the yield of alkene formed is 50%. The mass of the product formedis (at. mass of chlorine = 35.5)

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Solution:

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Molar mass of ethyl chloride
$= 2 \times 1 2 + 5\times 1 + 1 \times35.5$
$=24+9+35.5=64.5\,g\,mol^{-1}$
Molar mass of ethene $=2+12+4\times1$
$=28\,g\,mol^{-1}$
Actual yield $=50\%$ of $28\,g=14\,g$
$64.5\, g$ of ethyl chloride on dehydrohalogenation gives $14\, g$ ethene
$\therefore 32.25\,g$ of ethyl chloride on dehydrohalo- genation will give ethene $=7\,g$