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Q. When $3.00\, g$ of a substance ' $X$ ' is dissolved in $100\, g$ of $CCl _{4}$, it raises the boiling point by $0.60\, K$. The molar mass of the substance ' $X$ ' is_______ $g\, mol ^{-1}$. (Nearest integer).
[ Given $K _{b}$ for $CCl _{4}$ is $5.0\, K\,kg\,mol ^{-1}$ ]

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Solution:

$\Delta T_{b}=K_{b} \times$ molality
$0.60=5 \times\left(\frac{3 / M}{100 / 100}\right)$
$M=250$