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  4. When 100 ml of ( M /10) H 2 SO 4 is mixed with 500 ml of ( M /10) NaOH then nature of resulting solution and normality of excess of reactant left is

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Q. When $100\, ml$ of $\frac{ M }{10} H _{2} SO _{4}$ is mixed with $500\, ml$ of $\frac{ M }{10} NaOH$ then nature of resulting solution and normality of excess of reactant left is

Some Basic Concepts of Chemistry

Solution:

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$\left[\right.$ because $N = M \times n , n$ factor of $H _{2} SO _{4}=2$
$\therefore $ meq of $H _{2} SO _{4}=\left(100 \times \frac{1}{5}\right)=20$ meq
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[because $N$ factor is 1]
$\therefore $ meq of $NaOH =\left(500 \times \frac{1}{10}\right)=50$ meq
For Neutralisation Reaction $=\frac{\text { larger meq }-\text { smaller meq }}{\text { Total volume }}$
$=\frac{50-20}{600}=\frac{1}{20} N NaOH$ [because larger meq of NaOH will remain]
$\therefore $ Solution will be basic