1. Tardigrade
  2. Question
  3. Physics
  4. When 100 g of boiling water at 100° C is added into a calorimeter containing 300 g of cold water at 10° C, temperature of the mixture becomes 20° C. Then a metallic block of mass 1 kg at 10° C is dipped into the mixture in the calorimeter. After reaching thermal equilibrium, the final temperature becomes 19° C. What is the specific heat of the metal in C.G.S. unit?

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Q. When $100\, g$ of boiling water at $100^{\circ} C$ is added into a calorimeter containing $300\, g$ of cold water at $10^{\circ} C$, temperature of the mixture becomes $20^{\circ} C$. Then a metallic block of mass $1 \,kg$ at $10^{\circ} C$ is dipped into the mixture in the calorimeter. After reaching thermal equilibrium, the final temperature becomes $19^{\circ} C$. What is the specific heat of the metal in C.G.S. unit?

WBJEEWBJEE 2020

Solution:

Let, heat capacity of calorimeter $= ms$
$100 \times 1 \times 80=300 \times 1 \times 10+ ms \times 10$
$\therefore ms =500\, Cal /{ }^{\circ} C$
Again, $(100+300) \times 1 \times 1+500 \times 1$
$=1000 \times S_{b} \times 9$
$\therefore S_{b}=0.1\, Cal / g ^{\circ} C$