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Q. When 1 mol $Co\left(NH_{3}\right)_{5}Cl_{3}$ is treated with excess of $AgNO_{3}, 2$ mol of $AgCl$ are obtained. The formula of the complex is

Coordination Compounds

Solution:

$2$ mol of $AgCl$ means $2Cl^{-}$ are given in the solution hence, the formula of the complex will be$\left[Co\left(NH_{3}\right)_{5}Cl\right]Cl_{2}$.