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  4. When 0.1 mol CoCl3(NH3)5 is treated with excess of AgNO3, 0.2 mol of AgCl are obtained. The conductivity of solution will correspond to

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Q. When $0.1\, mol \,CoCl_{3}(NH_{3})_{5}$ is treated with excess of $AgNO_{3}$, $0.2$ mol of $AgCl$ are obtained. The conductivity of solution will correspond to

Coordination Compounds

Solution:

$0.2$ mol of $AgCl$ are obtained when $0.1$ mol $CoCl_{3}(NH_{3})_{5}$ is treated with excess of $AgNO_{3}$ which shows that one molecule of the complex gives two $Cl^{-}$ ions in solution. Thus, the formula of the complex is $[Co(NH_{3})_{5}Cl]Cl_{2}$ i.e., $1 : 2$ electrolyte.