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Chemistry
What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?
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Q. What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?
The d-and f-Block Elements
A
$Cr^{3+}$ and $Cr_2O^{2-}_7$ are formed
17%
B
$Cr_2O_7^{2-}$ and $H_2O$ are formed
33%
C
$CrO^{2-}_4$ is reduced to $+3$ state of $Cr$
33%
D
$CrO^{2-}_4$ is oxidised to $+7$ state of $Cr$
17%
Solution:
Dilute nitric acid converts chromate into dichromate and $H_2O$.
