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Q.
What will be the product obtained when $ (CH_3)_2CHCHO $ is treated with $ NaOH $ at $ 200^{\circ} C $ ?
J & K CETJ & K CET 2017Aldehydes Ketones and Carboxylic Acids
Solution:
$\underset{\text{2-Methylpopanal}}{{ 2\left(CH_{3}\right)_{2}CHCHO}}\xrightarrow[{200^{\circ}C}]{{NaOH} }$
$2$-Methylpropanol undergoes Cannizzaro reaction on treating with $NaOH$ at high temperature even it contains an $\alpha$-hydrogen. This is an exceptional behaviour, it should undergo aldol reaction but it does not, as carbanion formed is unstable
