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  4. What will be the pressure exerted by 16 g of methane in a 250 mL container at 300 K using ideal gas equation?

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Q. What will be the pressure exerted by $16\, g$ of methane in a $250\, mL$ container at $300\, K$ using ideal gas equation?

States of Matter

Solution:

Given, $16\, g$ of $CH _{4}=\frac{16}{16}=1\, mol$

The ideal gas equation predicts that the pressure exerted will be,

$P=\frac{n R T}{V}=\frac{1 \times 0.0821 \times 300}{0.250}=98.52\, atm$