Q. What will be the position number of isomers in $ {{C}_{2}}{{H}_{4}}C{{l}_{2}} $ ?
Rajasthan PMTRajasthan PMT 1998
Solution:
The position isomer is 2 of $ {{C}_{2}}{{H}_{4}}C{{l}_{2}} $ $ \underset{\begin{smallmatrix} 1-2\,\,dichloro\,ethane \\ ethylene\,chloride \end{smallmatrix}}{\mathop{\underset{C{{H}_{2}}-Cl}{\overset{C{{H}_{2}}-Cl}{\mathop{|}}}\,}}\, $
