Question

What will be the position number of isomers in ${{C}_{2}}{{H}_{4}}C{{l}_{2}}$ ?

• A. $3$
• B. $2$
• C. $1$
• D. zero

Answer 1

Answer: (B)

The position isomer is 2 of ${{C}_{2}}{{H}_{4}}C{{l}_{2}}$ $\underset{\begin{smallmatrix} 1-2\,\,dichloro\,ethane \\ ethylene\,chloride \end{smallmatrix}}{\mathop{\underset{C{{H}_{2}}-Cl}{\overset{C{{H}_{2}}-Cl}{\mathop{|}}}\,}}\,$