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Q. What will be the pH value of 0.05 M $ Ba{{(OH)}_{2}} $ solution?

WBJEEWBJEE 2006

Solution:

$ 0.05\,M\,Ba{{(OH)}_{2}} $ Solution $ \cong 2\times 0.5N\,Ba{{(OH)}_{2}} $ $ \cong 0.10\,N\,\,Ba{{(OH)}_{2}} $ $ \therefore $ $ pOH=-\log [O{{H}^{-}}] $ $ =-\log (0.10)=1 $ $ pH=14-pOH=14-1=13 $