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Q.
What will be the osmotic pressure in pascals exerted by a solution prepared by dissolving $1.0\, g$ of polymer of molar mass $150,000$ in $500 \,mL$ of water at $37 \,{}^°C$ ?
Solutions
Solution:
No. of moles of polymer $= \frac{1}{150,000}$
$\pi = CRT = \frac{n}{V} RT$
$\pi = \frac{1}{150,000} \times \frac{8.314 \times10^{3}\times310}{0.5}$
$= 34.36\,Pa$
$\left(R = 8.314 \times 10^{3}\, Pa\, L \,K^{-1}\, mol^{-1}\right)$