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Q. What will be the molarity of the solution in which $0.365\, g$ of $HCl$ gas is dissolved in $100 \,mL$ of solution?

Some Basic Concepts of Chemistry

Solution:

No. of moles in $0.365\, g$ of $HCl =\frac {0.365}{36.5} = 0.01$
Volume of solution in $L = \frac{100}{1000} = 0.1\, L$
Molarity $= \frac{n}{V(in L)} = \frac{0.01}{0.1} = 0.1 \,M$