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Q.
What will be the molar solubility $S$ of a solid salt with general formula $M_{x}^{p+} X_{y}^{q-}$ ?
Equilibrium
Solution:
A solid salt of the general formula, $M_{x}^{p+} X_{y}^{q-}$ with molar solubility $S$ in equilibrium with its saturated solution may be represented by the equation,
$M_{x} X_{y}(s) \longrightarrow x M^{p+}(a q)+y X^{q-}(a q)$
$\left(\right.$, where $\left.x \times p^{+}=y \times q^{-}\right)$
and its solubility product constant is given by
$K_{ sp } =\left[M^{p+}\right]^{x}\left[X^{q-}\right]^{y}=(x S)^{x}(y S)^{y} $
$K_{ sp } =x^{x} \cdot y^{y} \cdot S^{(x+y)}$
$S^{(x+y)} =\frac{K_{ sp }}{x^{x} \cdot y^{y}} $
or $ S=\left(K_{ sp } / x^{x} \cdot y^{y}\right)^{1 / x+y}$