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Q. What will be the molality of chloroform in the water sample which contains $15\, ppm$ chloroform by mass?

Some Basic Concepts of Chemistry

Solution:

$15\, ppm = \frac{15}{10^{6}} \times 10^{2} = 1.5 \times 10^{-3}\, g$
Molality of $CHCl_{3}$ solution $= \frac{1.5\times10^{-3}}{100} \times \frac{1000}{119.5}$
$=1.25\times10^{-4}\,m$