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Q. What will be the magnitude of electric field at point $O$ as shown in figure?
Each side of the figure is $\mid$ and perpendicular to each other?Physics Question Image

JEE MainJEE Main 2021Electric Charges and Fields

Solution:

$E_{1}=\frac{k q}{l^{2}}=E_{2}$
$E_{3}=\frac{k q}{(\sqrt{2} l)^{2}}=\frac{k q}{2 l^{2}}$
$E=\frac{\sqrt{2} k q}{l^{2}}-\frac{k q}{2 l^{2}}$
$=\frac{k q}{2 l^{2}}(2 \sqrt{2}-1)$

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