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Q. What will be the ionisation constant of formic acid if its $0.01 \,M$ solution is $14.5\%$ ionised?

Equilibrium

Solution:

$K_{a}=c\alpha^{2}$
$\alpha=\frac{14.5}{100}=0.15$
$K_{a}=0.01\times\left(0.145\right)^{2}$
$=2.1\times10^{-4}$