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Q. What will be the half-life period of a first order reaction with rate constant $k=5.5 \times 10^{-14} s^{-1}$ ?

Haryana PMTHaryana PMT 2010Chemical Kinetics

Solution:

For the first order reaction,
$\because t_{1 / 2}=\frac{0.693}{k} $
$\therefore =\frac{0.693}{5.5 \times 10^{-14} s^{-1}} $
$t_{1 / 2}=1.26 \times 10^{13} s$