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Chemistry
What will be the Freundlich's adsorption isotherm equation at high pressure?
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Q. What will be the Freundlich's adsorption isotherm equation at high pressure?
NTA Abhyas
NTA Abhyas 2020
Surface Chemistry
A
$\frac{\text{x}}{\text{m}}=\text{k}$
29%
B
$\frac{\text{x}}{\text{m}}=\text{k}\text{p}$
29%
C
None of these
29%
D
$\frac{\text{x}}{\text{m}} \text{=} \frac{\text{k}}{\text{p}}$
14%
Solution:
Freundlich's adsorption isotherm is given as:
$\frac{\text{x}}{\text{m}} \text{=Kp}^{\frac{1}{n}}$
$\text{W}\text{h}\text{e}\text{n} \, \text{x}=1,\frac{\text{x}}{\text{m}}=\text{k}\text{p} \, \left(\text{a} \text{t} \, \text{l} \text{o} \text{w} \, \text{p} \text{r} \text{e} \text{s} \text{s} \text{u} \text{r} \text{e}\right)$
$\text{W}\text{h}\text{e}\text{n} \, \text{n}>1,\frac{\text{x}}{\text{m}}=\text{k }\left(\text{a} \text{t} \, \text{h} \text{i} \text{g} \text{h} \, \text{p} \text{r} \text{e} \text{s} \text{s} \text{u} \text{r} \text{e}\right)$