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Q. What will be the emf of the following concentration cell at $25^{\circ}C$?
$Ag_{\left(s\right)}\left|AgNO_{3}\left(0.01\,M\right)\right|\left|AgNO_{3}\left(0.05\,M\right)\right|Ag_{\left(s\right)}$

Electrochemistry

Solution:

$E=E^{\circ}-\frac{0.0591}{n}log\,Q$
$E^{\circ}=0$ for all concentration cells
$=0-\frac{0.0591}{1} log \left(\frac{0.01}{0.05}\right)$
$=0.0413\,V$