Question

What will be the amount of energy absorbed when an electron jumps from first orbit to second orbits? (If the value of energy in $n$th orbit of $H$-atom is expressed as $\left.E_{n}=-\frac{13.6}{n^{2}} eV \right)$

• A. - 3.4 eV
• B. - 6.6 eV
• C. -8.1 eV
• D. -10.2 eV

Answer 1

Answer: (D)

Energy of $n$th orbit of hydrogen atom
$E_{n}=-\frac{13.6}{n^{2}} eV$
The energy absorbed, when an electron jumps from the first energy level $(n=1)$ to second level $(n=2)$
$=-13.6 \times\left(\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right)$
$=-13.6\left[\frac{1}{(1)^{2}}-\frac{1}{(2)^{2}}\right]$
$=-13.6 \times \frac{3}{4}$
$=-10.2\, eV$