1. Tardigrade
  2. Question
  3. Chemistry
  4. What will be p H of the following half-cell Pt, H 2 H 2 SO 4 ? The oxidation potential is + 0.3 V.

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. What will be $p H$ of the following half-cell $Pt, H _{2} H _{2} SO _{4}$ ? The oxidation potential is $+ 0.3\,V.$

AMUAMU 2015Electrochemistry

Solution:

$H_{2} \rightarrow 2 H^{+}+2 e^{-}$
$\because E_{\text {cell }}=E_{\text {cell }}^{o}-\frac{0.0591}{n} \log _{10} \frac{\left[H^{+}\right]^{2}}{\left[H_{2}\right]}$
$\therefore 0.3=0-\frac{0.0591}{2} \log _{10}\left[H^{+}\right]^{2}$
or $-\log \left[H^{+}\right]=\frac{0.3}{0.0591}=5.085$
$\therefore p H-\log \left[H^{+}\right]$
$=5.085$