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  4. What will be pH of 5.0 × 10-2 M NaOH solution? ( log 2=0.3)

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Q. What will be $pH$ of $5.0 \times 10^{-2} M NaOH$ solution?
$(\log 2=0.3)$

JIPMERJIPMER 2019

Solution:

Given $\left[ OH ^{-}\right]=5 \times 10^{-2}$
$\therefore pOH =-\log 5 \times 10^{-2}$
$=-\log 5+2 \log 10=1.30$
$\because pH + pOH =14$
$\because pH =14- pOH$
$=14-1.30=12.70$