Q.
What will be output of the following logic gate, if input of $(A=0, B=1)$ is provided?
Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
The given logic gate is,
Truth table of the above gate, for inputs $(0,1)$,
$A$
$B$
$\bar{A}$
$C = \bar{A} + B$
$D= \overline{A \cdot B}$
$C + D$
$Y = (\overline{C+D})$
$0$
$1$
$1$
$1$
$1$
$1$
$0$
$A$ | $B$ | $\bar{A}$ | $C = \bar{A} + B$ | $D= \overline{A \cdot B}$ | $C + D$ | $Y = (\overline{C+D})$ |
---|---|---|---|---|---|---|
$0$ | $1$ | $1$ | $1$ | $1$ | $1$ | $0$ |