In steady state, arm having capacitors does not flow current. So, we can neglect them
$\therefore $ The given circuit reduce to
$\therefore R_{net} = 200 + 400 = 600\,\Omega$
$\therefore $ Current in circuit,
$I = \frac{V}{R} = \frac{6}{600} = 0.01\,A$
$ = 10\,mA$