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  4. What weight of oxalic acid (H2C2O4 2H2O ) is required to prepare 1,000 mL of N/10 solution?

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Q. What weight of oxalic acid $(H_{2}C_{2}O_{4} 2H_{2}O )$ is required to prepare 1,000 mL of N/10 solution?

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Solution:

Eq. wt. of oxalic acid
$=\frac{\text{Mol.wt}}{\text{Basicity}} =\frac{\text{Mol.wt}}{2}=\frac{126}{2}=63$
Weight of oxalic acid required to prepare 1000 mL
$\frac{N}{10}$ solution $=6.3\,g $