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Q. What weight of $ HCl $ is present in $ 155\, ml $ of a $ 0.54\, M $ solution?

AMUAMU 2016Some Basic Concepts of Chemistry

Solution:

$HCl$; molecular weight $= 36.4\,g/mol$
$M = (g/mw)/ L$
$M \cdot L= g/m w$
$mw \times m \times L = g$
$g = (36.4 \,g/mol)(0.54 \,mol/L)$
$(155 \,mL) (1L/1000\, mL)$
$g = 3.04 g \simeq 3.06 \,g$