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  4. What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition n=4 to n=2 of He +spectrum?

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Q. What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition $n=4$ to $n=2$ of $He ^{+}$spectrum?

Solution:

$\frac{1}{\lambda}=R_{H} Z^{2}\left[\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right]$