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Q.
What products are formed when the following compound is treated with $Br_2$ in the presence of $FeBr_3$?
Hydrocarbons
Solution:
$ -CH_3$ group is $o,p$-directing. Because of crowding, no substitution occurs at the carbon atom between the two
$-CH_3$ groups in $m$-Xylene, even though two $-CH_3$ groups activate that position
