Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. What percentage of kinetic energy of a moving particle is transferred to a stationary particle when it strikes the stationary particle of $5$ times its mass? (Assume the collision to be head-on elastic collision)

JEE MainJEE Main 2022Work, Energy and Power

Solution:

Velocity after collision
$V_{2}=\frac{\left(m_{2}-m_{1}\right) u_{2}+2 m_{1} u_{1}}{m_{1}+m_{2}} $
$V_{2}=\frac{(5 m-m) 0+2 m \cdot u_{0}}{m+5 m}=\frac{u_{0}}{3} $
$\% \Delta K E=\frac{\frac{1}{2} 5 m\left(\frac{u_{0}}{3}\right)^{2}-0}{\frac{1}{2} m u_{0}^{2}} \times 100 $
$=\frac{5 u_{0}^{2}}{9 u_{0}^{2}} \times 100=\frac{500}{9}=55.6 \%$