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  4. What mass of CaCO3 is required to react completely with 25 ml of 0.75 M HCl according to the reaction CaCO3(s)+2HCl(aq) arrow CaCl2(aq)+CO2(g)+H2O(l)

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Q. What mass of $CaCO_{3}$ is required to react completely with 25 ml of 0.75 M HCl according to the reaction $CaCO_{3}\left(s\right)+2HCl\left(aq\right) \rightarrow CaCl_{2}\left(aq\right)+CO_{2}\left(g\right)+H_{2}O\left(l\right)$

NTA AbhyasNTA Abhyas 2020Some Basic Concepts of Chemistry

Solution:

$CaCO _{3}( s )+2 HCl ( aq ) \rightarrow CaCl _{2}( aq )+ CO _{2}( g )+ H _{2} O ( l )$

Moles present in $25 ml$ of $0.75 M HCl =\frac{0.75}{ l 000} \times 25$

$=0.01875$ moles

Since 2 moles react completely with $CaCO _{3}=100 g$

0.01875 moles react completely with $CaCO _{3}=\frac{100}{2} \times 0.01875$

$=0.9375 g$