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Q. What is $Z$ in following reaction
$CuSO_{4} + Z \to Cu_{3}P_{2} +H_{2}SO_{4}$
$HgCl_{2} + Z \to Hg_{3}P_{2} +HCl$

The p-Block Elements - Part2

Solution:

$3 CuSO _{4}+2 PH _{3} \rightarrow Cu _{3} P _{2}+3 H _{2} SO _{4}$
$3 HgCl _{2}+2 PH _{3} \rightarrow Hg _{3} P _{2}+6 HCl$