Question

What is $x$ in the following reaction?
$Al ( s )+ NaOH ( aq )+ H _2 O ( l ) \rightarrow x+ H _2( g )$

• A. $Na _2\left[ Al ( OH )_4\right]^{-}$
• B. $Na ^{+}\left[ Al ( OH )_4{ }^{-}\right.$
• C. $Na _2\left[ Al ( OH )_6\right]^-$
• D. $Na ^{+}\left[ Al ( OH )_6\right]^{-}$

Answer 1

Answer: (B)

$2 Al ( s )+2 NaOH ( aq ) +6 H _2 O ( l ) \rightarrow 2 Na ^{+}\left[ Al ( OH )_4\right]^{-}( aq )+3 H _2( g ) $