Thank you for reporting, we will resolve it shortly
Q.
What is the weight of oxygen that is required for the complete combustion of $2.8\, kg$ of ethylene?
AMUAMU 2004
Solution:
On the combustion of ethylene carbon dioxide and water are formed.
$\underset{12 \times 2 +4 =28}{C _{2} H _{4}} + \underset{96}{3O _{2}} \longrightarrow 2 CO _{2}+2 H _{2} O$
$\because$ The weight of oxygen required for complete combustion of $28 g$ of ethylene $=96\, g$
$\therefore $ The weight of oxygen required for complete combustion of $2.8\, kg$ of ethylene
$=\frac{96 \times 2.8 \times 1000}{28}$
$=9600\, g =9.6\, kg$